# Can you really reduce kVA billing after installing power capacitors?

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## Stubborn factory owners

This technical article I dedicate to stubborn factory owners who still don’t believe and don’t want to spend the money on optimizing the factory costs.

Not all of them are like that, but the most of them ‘not-much-electrically-educated’ are. So, let’s start with explaining.

The fact is that power capacitors provide many benefits, and among them //

• Reduced electric utility bills
• Increased system capacity
• Improved voltage
• Reduced losses

### Reduced utility bills is not an imagination

Your electric utility provides working (kW) and reactive power (kVAR) to your plant in the form of apparent power (kVA).

While reactive power (kVAR) doesn’t register on kW demand or kW hour meters, the utility’s transmission and distribution system must be large enough to provide the total power. Utilities have various ways of passing the expense of larger generators, transformers, cables, switches, and the like, along to you.

As shown in the following case histories, capacitors can save you money no matter how your utility bills you for power.

### kVA billing

In case you didn’t know, the utility measures and bills every ampere of current, including reactive current. Let’s observe the optimizing costs in the following two cases, but before this, please jump and read what’s common for beer mug and power factor? Your eyes will open :)

#### Case 1 //

Assume an uncorrected 460 kVA demand, 480V, three-phase at 0.87 power factor (normally good).

Billing:
\$4.75/kVA demand
Correct to 0.97 power factor

Solution:
kVA × power factor = kW
460 × 0.87 = 400 kW actual demand
kW = kVA PF
400 = 412 corrected billing demand 0.97

From Table 1, kW multipliers, to raise the power factor from 0.87 to 0.97 requires capacitor:
Multiplier of 0.316 x kW
0.316 x 400 = 126 kVAR (use 140 kVAR)

Uncorrected original billing:
460 kVA × \$4.75 = \$2185 / month – \$1957
= \$ 228 / month savings × 12
= \$2736 annual savings

Corrected new billing:
412 kVA × \$4.75 = \$1957/month
140 kVAR, 480V capacitor cost: \$1600 (installation extra).

This capacitor pays for itself in less than eight months.

#### Case 2 //

Assume the same conditions except that:

• 400 kW at 87% = 460 kVA
• 400 kW at 97% = 412 kVA corrected billing

kVA demand charge:
\$1.91 / kVA / month (112,400 kWh / month energy consumed)

Energy charge:
\$0.0286 / kWh (first 200 kWh / kVA of demand)
\$0.0243 / kWh (next 300 kWh / kVA of demand)
\$0.021 / kWh (all over 500 kWh / kVA of demand)

Uncorrected:
460 kVA × \$1.91 = \$878.60 – \$786.92
\$ 91.68 savings in demand charge

￼Corrected:
412 kVA × \$1.91 = \$786.92

Uncorrected energy:
kWh = 112,400
460 × 200 = 92,000 kWh
at 0.0286 = \$2631.20

460 × 300 = 138,000
but balance only = 20,400
at \$0.0243 = \$495.72

\$2631.20 + \$ 495.72
\$3126.92 uncorrected energy charge

Corrected energy:
kWh = 112,400
460 × 200 = 82,400 kWh
at 0.0286 = \$2356.64

460 × 300 = 123,600
but balance only = 30,000
at \$0.0243 = \$729.00

\$2356.64 + \$ 729.00
\$3085.64 corrected energy charge

\$3126.92 – \$3085.64
\$ 41.28 savings in energy charge due to rate charge

(9600 kWh in first step reduced by \$0.0043)

This is not a reduction in energy consumed, but in billing only.
\$ 41.28 energy – \$ 91.68 demand
\$ 132.96 monthly total savings × 12  = \$1595.52

A 130 kVAR capacitor can be paid for in less than 14 months.

### Table 1 //

Multipliers to Determine Capacitor Kilovars Required for Power Factor Correction

### Installing a capacitor bank (VIDEO)

Reference // Power factor correction: a guide for the plant engineer – ABB

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#### Edvard Csanyi

Electrical engineer, programmer and founder of EEP. Highly specialized for design of LV/MV switchgears and LV high power busbar trunking (<6300A) in power substations, commercial buildings and industry fascilities. Professional in AutoCAD programming. Present on

1. uday
Jul 29, 2016

Have you ever considered installing capacitor banks at individual loads.
If yes, on what basis???

2. Audi
Oct 02, 2015

460 × 200 = 82,400 kWh
at 0.0286 = \$2356.64

how is it 460 X 200 = 82,400??

• bowo
Nov 23, 2015

460x200x0.9=82800

Sep 08, 2015

Hi, i want to ask in the first case when you say 400=412 , the 412 come from the 460 KVA * 0,97 PF ?Thanks in advance .

4. Miguel Bas
Sep 05, 2015

After the installation the customer has to notify (utility company) the power factor correction to test, verification and the proper certification. Finally the utility make a change in the load contract and in the next bill the customer has a cost benefit.

Sep 04, 2015

PFC companies obtain KVA, kwh, utility bill etc for about 6 months before installation ,then after installation they take readings and show client that their predictions are correct.

• Phil
Sep 23, 2015

Yes power factor corecting capacitors fitted at the main supply of an installation will absoulety reduce the electricity bills.

I would love to talk about the science behind it but I know that the layman would not get it.

All you need to understand is that as long as you have mostly inductive loads (not resistive loads) then you can save money on your bills.

• Tony Stewart
Dec 15, 2015

What if arc welders make up 50 % of peak demand and this is asynchronous pulsed current?
How does resonant frequency; typically chane with optimum Cpf table

How is EMI affected in both conducted and radiated? Worse or better?
Line impedance vs f will be reduced significantly with passive PFC to raise impulse currents from avalanche effects from arc welds.