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Examples Of Power Supply Protection

As industrial operations processes and plants have become more complex and extensive, the requirement for improved reliability of electrical power supplies has also increased.

Protection And Control Of Industrial Power Supply Systems (Relay Schemes And Settings)
Protection And Control Of Industrial Power Supply Systems (Relay Schemes And Settings) - on photo MiCOM protection relays

The potential costs of outage time following a failure of the power supply to a plant have risen dramatically as well. The protection and control of industrial power supply systems must be given careful attention. Many of the techniques that have been evolved for EHV power systems may be applied to lower voltage systems also, but typically on a reduced scale.

However, industrial systems have many special problems that have warranted individual attention and the development of specific solutions.

Many industrial plants have their own generation installed. Sometimes it is for emergency use only, feeding a limited number of busbars and with limited capacity. This arrangement is often adopted to ensure safe shutdown of process plant and personnel safety.

In other plants, the nature of the process allows production of a substantial quantity of electricity, perhaps allowing export of any surplus to the public supply system – at either at sub-transmission or distribution voltage levels. Plants that run generation in parallel with the public supply distribution network are often referred to as co-generation or embedded generation.

In this technical article, the following examples of protection & control of industrial power supply systems are considered:

  1. Fuse Co-ordination
  2. Grading of Fuses / MCCBs / Overcurrent Relays
    1. Determination of relay current setting
    2. Relay characteristic and time multiplier selection
  3. Protection of a Dual-Fed Substation
    1. General considerations
    2. Motor protection relay settings
    3. Relay B settings
    4. Relays C settings
    5. Comments on grading

1. Fuse Co-ordination

An example of the application of fuses is based on the arrangement in Figure 1(a). This shows an unsatisfactory scheme with commonly encountered shortcomings.

It can be seen that fuses B, C and D will discriminate with fuse A, but the 400A sub-circuit fuse E may not discriminate, with the 500A sub-circuit fuse D at higher levels of fault current.

Fuse protection: effect of layout on discrimination - Incorrect layout giving rise to problems in discrimination
Figure 1(a) – Fuse protection: effect of layout on discrimination – Incorrect layout giving rise to problems in discrimination

The solution, shown in Figure 1(b), is to feed the 400A circuit E direct from the busbars. The sub-circuit fuse D may now have its rating reduced from 500A to a value, of say 100A, appropriate to the remaining sub-circuit.

This arrangement now provides a discriminating fuse distribution scheme satisfactory for an industrial system.

Fuse protection: effect of layout on discrimination - Incorrect layout and discrimination
Figure 1(b) – Fuse protection: effect of layout on discrimination – Incorrect layout and discrimination

However, there are industrial applications where discrimination is a secondary factor. In the application shown in Figure 2, a contactor having a fault rating of 20kA controls the load in one sub-circuit.

A fuse rating of 630A is selected for the minor fuse in the contactor circuit to give protection within the through-fault capacity of the contactor.

Example of back-up protection
Figure 2 – Example of back-up protection

The major fuse of 800A is chosen, as the minimum rating that is greater than the total load current on the switchboard. Discrimination between the two fuses is not obtained, as the pre-arcing I2t of the 800A fuse is less than the total I2t of the 630A fuse.

Therefore, the major fuse will blow as well as the minor one, for most faults, so that all other loads fed from the switchboard will be lost.

This may be acceptable in some cases. In most cases, however, loss of the complete switchboard for a fault on a single outgoing circuit will not be acceptable, and the design will have to be revised.

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2. Grading of Fuses / MCCBs / Overcurrent Relays

An example of an application involving a moulded case circuit breaker, fuse and a protection relay is shown in Figure 3.

A 1MVA 3.3kV/400V transformer feeds the LV board via a circuit breaker, which is equipped with an Alstom MiCOM P14x numerical relay having a setting range of 8-400% of rated current and fed from 2000/1A CTs.

Network diagram for protection co-ordination example - fuse / MCCB / relay
Figure 3 – Network diagram for protection co-ordination example – fuse / MCCB / relay

Discrimination is required between the relay and both the fuse and MCCB up to the 40kA fault rating of the board. To begin with, the time/current characteristics of both the 400A fuse and the MCCB are plotted in Figure 18.19.

2a. Determination of relay current setting

The relay current setting chosen must not be less than the full load current level and must have enough margin to allow the relay to reset with full load current flowing.

The latter may be determined from the transformer rating:

Full load current

With the CT ratio of 2000/1A and a relay reset ratio of 95% of the nominal current setting, a current setting of at least 80% would be satisfactory, to avoid tripping and/or failure to reset with the transformer carrying full load current.

However, choice of a value at the lower end of this current setting range would move the relay characteristic towards that of the MCCB and discrimination may be lost at low fault currents.

It is therefore prudent to select initially a relay current setting of 100%.

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2b. Relay characteristic and time multiplier selection

An EI characteristic is selected for the relay to ensure discrimination with the fuse.

From Figure 4, it may be seen that at the fault level of 40kA the fuse will operate in less than 0.01s and the MCCB operates in approximately 0.014s. Using a fixed grading margin of 0.4s, the required relay operating time becomes 0.4 + 0.014 = 0.414s.

With a CT ratio of 2000/1A, a relay current setting of 100%, and a relay TMS setting (Time Multiplier Setting) of 1.0, the extremely inverse curve gives a relay operating time of 0.2s at a fault current of 40kA. This is too fast to give adequate discrimination and indicates that the EI curve is too severe for this application. Turning to the VI relay characteristic, the relay operation time is found to be 0.71s at a TMS of 1.0.

To obtain the required relay operating time of 0.414s:

TMS setting = 0.414 / 0.71 = 0.583

Use a TMS of 0.6, nearest available setting.

The use of a different form of inverse time characteristic makes it advisable to check discrimination at the lower current levels also at this stage. At a fault current of 4kA, the relay will operate in 8.1s, which does not give discrimination with the MCCB. A relay operation time of 8.3s is required.

To overcome this, the relay characteristic needs to be moved away from the MCCB characteristic, a change that may be achieved by using a TMS of 0.625. The revised relay characteristic is also shown in Figure 4.

Grading curves for Fuse / MCCB / relay grading example
Figure 4 – Grading curves for Fuse / MCCB / relay grading example

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3. Protection of a Dual-Fed Substation

As an example of how numerical protection relays can be used in an industrial system, consider the typical large industrial substation of Figure 5 below. Two 1.6MVA, 11/0.4kV transformers feeding a busbar whose bus-section CB is normally open.

The LV system is solidly earthed. The largest outgoing feeder is to a motor rated 160kW, 193kVA, and a starting current of 7 x FLC.

Relay grading example for dual-fed switchboard
Figure 5 – Relay grading example for dual-fed switchboard

The transformer impedance is to IEC standards. The LV switchgear and busbars are fault rated at 50kA rms. To simplify the analysis, only the phase-fault LV protection is considered.

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3a. General considerations

Analysis of many substations configured as in Figure 5 above shows that the maximum fault level and feeder load current is obtained with the bus-section circuit breaker closed and one of the infeeding CBs open. This applies so long as the switchboard has a significant amount of motor load.

The contribution of motor load to the fault level at the switchboard is usually larger than that from a single infeeding transformer, as the transformer restricts the amount of fault current infeed from the primary side.

The three-phase break fault level at the switchboard under these conditions is assumed to be 40kA rms.

Relays C1 and C2 are not required to have directional characteristics (read more about it below) as all three circuit breakers are only closed momentarily during transfer from a single infeeding transformer to two infeeding transformers configuration.

This transfer is normally an automated sequence, and the chance of a fault occurring during the short period (of the order of 1s) when all three CBs are closed is taken to be negligibly small. Similarly, although this configuration gives the largest fault level at the switchboard, it is not considered from either a switchboard fault rating or protection viewpoint.

It is assumed that modern numerical relays are used. For simplicity, a fixed grading margin of 0.3s is used.

Application of Directional Relays

If non-unit, non-directional relays are applied to parallel feeders having a single generating source, any faults that might occur on any one line will, regardless of the relay settings used, isolate both lines and completely disconnect the power supply.

With this type of system configuration, it is necessary to apply directional relays at the receiving end and to grade them with the non-directional relays at the sending end, to ensure correct discriminative operation of the relays during line faults.

This is done by setting the directional relays R’1 and R’2 in Figure 6 with their directional elements looking into the protected line, and giving them lower time and current settings than relays R1 and R2.

The usual practice is to set relays R’1 and R’2 to 50% of the normal full load of the protected circuit and 0.1 TMS, but care must be taken to ensure that the continuous thermal rating of the relays of twice rated current is not exceeded.

Directional relays applied to parallel feeders
Figure 6 – Directional relays applied to parallel feeders

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3b. Motor protection relay settings

From the motor characteristics given, the overcurrent relay settings (Relay A) can be found using the following guidelines:

Thermal element
  • Current setting: 300A
  • Time constant: 20 mins
Instantaneous element
  • Current setting: 2.32kA

These are the only settings relevant to the upstream relays.

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3c. Relay B settings

Relay B settings are derived from consideration of the loading and fault levels with the bus-section breaker between busbars A1 and A2 closed. No information is given about the load split between the two busbars, but it can be assumed in the absence of definitive information that each busbar is capable of supplying the total load of 1.6MVA.

With fixed tap transformers, the bus voltage may fall to 95% of nominal under these conditions, leading to a load current of 2430A.

The IDMT current setting must be greater than this, to avoid relay operation on normal load currents and (ideally) with aggregate starting/re-acceleration currents.

If the entire load on the busbar was motor load, an aggregate starting current in excess of 13kA would occur, but a current setting of this order would be excessively high and lead to grading problems further upstream.

It is unlikely that the entire load is motor load (though this does occur, especially where a supply voltage of 690V is chosen for motors – an increasingly common practice) or that all motors are started simultaneously (but simultaneous re-acceleration may well occur).

What is essential is that relay B does not issue a trip command under these circumstances – i.e. the relay current/time characteristic is in excess of the current/time characteristic of the worst-case starting/re-acceleration condition.

It is therefore assumed that 50% of the total bus load is motor load, with an average starting current of 600% of full load current (= 6930A), and that re-acceleration takes 3s.

A current setting of 3000A is therefore initially used.

The SI characteristic is used for grading the relay, as co-ordination with fuses is not required. The TMS is required to be set to grade with the thermal protection of relay A under ‘cold’ conditions, as this gives the longest operation time of Relay A, and the re-acceleration conditions. A TMS value of 0.41 is found to provide satisfactory grading, being dictated by the motor starting/re-acceleration transient. Adjustment of both current and TMS settings may be required depending on the exact re-acceleration conditions.

Note that lower current and TMS settings could be used if motor starting/re-acceleration did not need to be considered.

The high-set setting needs to be above the full load current and motor starting/re-acceleration transient current, but less than the fault current by a suitable margin.

A setting of 12.5kA is initially selected. A time delay of 0.3s has to used to ensure grading with relay A at high fault current levels. Both relays A and B may see a current in excess of 25kA for faults on the cable side of the CB feeding the 160kW motor.

The relay curves are shown in Figure 6 below:

Grading of relays A and B
Figure 6 – Grading of relays A and B

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3d. Relays C settings

The setting of the IDMT element of relays C1 and C2 has to be suitable for protecting the busbar while grading with relay B. The limiting condition is grading with relay B, as this gives the longest operation time for relays C.

The current setting has to be above that for relay B to achieve full co-ordination, and a value of 3250A is suitable. The TMS setting using the SI characteristic is chosen to grade with that of relay B at a current of 12.5kA (relay B instantaneous setting), and is found to be 0.45.

The high-set element must grade with that of relay B, so a time delay of 0.62sec is required. The current setting must be higher than that of relay B, so use a value of 15kA.

The final relay grading curves and settings are shown in Figure 7.

Final relay grading curves
Figure 7 – Final relay grading curves

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3e. Comments on grading

While the above grading may appear satisfactory, the protection on the primary side of the transformer has not been considered.

IDMT protection at this point will have to grade with relays C and with the through-fault short-time withstand curves of the transformer and cabling. This may result in excessively long operation times. Even if the operation time at the 11kV level is satisfactory, there is probably a Utility infeed to consider, which will involve a further set of relays and another stage of time grading, and the fault clearance time at the Utility infeed will almost certainly be excessive.

One solution is to accept a total loss of supply to the 0.4kV bus under conditions of a single infeed and bus section CB closed.

This is achieved by setting relays C such that grading with relay B does not occur at all current levels, or omitting relay B from the protection scheme. The argument for this is that network operation policy is to ensure loss of supply to both sections of the switchboard does not occur for single contingencies.

As single infeed operation is not normal, a contingency (whether fault or maintenance) has already occurred, so that a further fault causing total loss of supply to the switchboard through tripping of one of relays B is a second contingency. Total loss of supply is therefore acceptable. The alternative is to accept a lack of discrimination at some point on the system.

Another solution is to employ partial differential protection to remove the need for Relay A, but this is seldom used. The strategy adopted will depend on the individual circumstances.

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Reference // Network protection & automation guide by Alstom Grid

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About Author


Edvard Csanyi

Electrical engineer, programmer and founder of EEP. Highly specialized for design of LV/MV switchgears and LV high power busbar trunking (<6300A) in power substations, commercial buildings and industry fascilities. Professional in AutoCAD programming. Present on


  1. David Renshaw
    Jan 03, 2018

    One further comment about fuse discrimination (or selectivity in American terminology): A manufacturer will typically state that a ratio of 1.6:1 is adequate to provide discrimination (e.g. a 100A fuse will discriminate against a 160A one), and will supply “I-squared t” figures that support this. But this assumes that both fuses are from the same manufacturer. In practice the designer can’t guarantee that a replacement fuse -even of the correct current rating- will come from the same firm. Therefore 2:1 would be a safer minimum ratio to ensure discrimination.

  2. David Renshaw
    Jan 03, 2018

    Thanks for the article. One glitch: In section 1 (fuse discrimination), Fig. 1a is actually a correct layout for proper discrimination but Fig. 1b would *not* discriminate (i.e with 500A and 400A fuses in series). This is in conflict with the wording, which describes scheme 1a as unsatisfactory & 1b as OK.

    Regards, David.

  3. BOUJNAH Khaled
    Jan 02, 2018

    très intéressant merci

  4. reza tousipanah
    Jan 02, 2018

    Would you please tell me the corona inception and extinction voltage calculation and test procedure with and without corona ring and related table for those voltages in 63,132,230 and 400 kv power line.
    Your kind attention and prompt reply will be appreciated.
    Best regards : Reza Tousipanah

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