## Introduction to test

The * no-load losses* are very much related to the operational performance of a transformer. As long as the transformer is operated,

*. For this reason, no load losses are very important for operational economy. No-load losses are also used in the heating test.*

**these losses occur**The no-load loss and current measurements of a transformer are made while one of the * windings* (

*usually the HV winding*)

*and the other winding is supplied at the rated voltage and frequency.*

**is kept open***and the*

**no-load current (Io)***are measured.*

**no-load losses (Po)**The measured losses depend heavily on the applied voltage waveform and frequency. For this reason, the waveform of the voltage should be * very sinusoidal* and

*.*

**at rated frequency**Normally, the measurements are made while the supply voltage is increased at equal intervals* from 90% to 115% of the transformer rated voltage (Un)* and this way the values at the rated voltage can also be found.

### No-load losses and currents

**The no-load losses of a transformer are grouped in three main topics:**

at the core of the transformer,**Iron losses**at the insulating material and**Dielectric losses**- The
due to no-load current.**copper losses**

The last two of them are very small in value and can be ignored.

**So, only the iron losses are considered in determining the no-load losses.**

### Measuring circuit and performing the measurement

In general according to the standards, if there is less than 3% difference between the * effective (U) value* and the

*, the shape of the wave is considered as appropriate for measurements.*

**average (U’) value of the supply voltage***and*

**effective (r.m.s.) value***of the voltage are*

**the average (mean) value***. If the readings of both voltmeter are equal, there is no need for correction.*

**different**During measurements, the supply voltage U´ is supplied to the transformer by the average value voltmeter. In this way, the foreseen induction is formed and as a result of this, the hysteresis losses are measured correctly. The eddy-current losses should be corrected according to equation below.

P_{m} = P_{0} · (P_{1} + k · P_{2})

**P _{m}**: Measured loss

**P**: No-load losses where the voltage is sinusoidal

_{0}Here: **P _{0} = P_{h} + P_{E} = k_{1} · f + k_{2} · f^{2}**

**k = [ U / U’ ] ^{2}**

**P _{1}**: The hysteresis loss ratio in total losses

**(P**

_{h}) = k_{1}· f**P**: The eddy-curent loss ratio in total losses

_{2}**(P**

_{E}) = k_{2}· f^{2}At 50 Hz and 60 Hz, in cold oriented sheet steel, **P _{1} = P_{2} = % 50**.

**So, the P**_{0}no-load loss becomes:P_{o} = P_{m} / (P_{1} + k · P_{2}) where **P _{1} = P_{2} = 0,5**

**According to IEC 60076-1:****P _{m} = P_{0} · (1 + d)** where

**d = [ (U’ – U) / U’ ]**

*.*

**average of the three phase currents**Before the no-load measurements, the transformer might have been * magnetised by direct current* and it’s components (

*resistance measurement or impulse tests*).

For this reason, the core has to be demagnetised. To do this, it has to be supplied by a voltage value (*increasing and decreasing between the maximum and minimum voltage values for a few minutes*) higher than the rated voltage for a certain time and then the measurements can be made.

The no-load currents are neither symmetrical nor of equal amplitude in three phase transformers. The phase angles between voltages and currents may be different for each of three phases.

* For this reason, the wattmeter readings on each of the three phases may not be equal.* Sometimes one of the wattmeter values can be

*(zero) or*

**0***(-).*

**negative****Resource:** Transformer Tests – BEST Transformers

joseph

Sir,

Why the wire size of the fusewire in structure is so small?

How can it possible to conduct high current?

samir rofail

Good morning

IA from Egypt . As electric manager of of the iron and steel Co

My point that we have 220kv/22.5 kv tr. 80 MIA had faced external School from the load side .trpped by different. ; boh. And so protection.

My question is the supplier need to do the following tests sc impedance . No load losses with reduced voltage . We need your opinion and support

Oscar Vasquez Romero

Que nivel de armónicos se generan en los inversores de DC AC utilizados en la generacion fotovoltaica y se esto incide al inyectar esta energía en un red de distribución electrica convencional, el nivel de armónicos se incremente en la misma????

Transformer Routine Test - Measurement of Voltage Ratio and Check of Phase Displacement | EEP

[…] and Check of Phase Displacement (on photo: OSB laboratory of BEST Transformers)IntroductionThe no-load voltage ratio between two windings of a transformer is called turn ratio.The aim of measurement is: Confirming […]