Search

Premium Membership ♕

Save 50% on all EEP Academy courses with Enterprise Membership Plan and study specialized LV/MV/HV technical articles & guides.

Home / Technical Articles / A comprehensive guide to correct calculation for transformer differential relay settings

For engineers and protection specialists

In this technical article, we will delve into the comprehensive methodology of calculating the differential relay settings for the GE P642 relay. Each step of the process will be explored, from data collection to final setting determination. By following these calculations meticulously, engineers and protection specialists can ensure the optimal performance of the relay in differential protection configuration.

A comprehensive guide to correct calculation for transformer differential relay settings
A comprehensive guide to correct calculation for transformer differential relay settings

Differential protection is a vital element in ensuring the reliable operation of power system equipment, particularly transformers. The GE P642 protection relay offers advanced differential protection capabilities, allowing for precise and effective fault detection. To harness the full potential of this relay, it is crucial to understand the process of calculating the appropriate relay settings.

The article will cover essential topics such as transformer full load currents, variations in current ratios caused by tap changer windings, calculations of CT secondary currents corresponding to high voltage (HV) and low voltage (LV), and the calculation of the ratio correction factor.

Furthermore, we will dive deep into the intricacies of bias current in differential protection, differential pickup current calculations, and differential slope calculations. To enhance the reliability and performance of the differential protection scheme, the article will discuss additional features such as current transformer supervision (CTS), high-set differential protection function, and harmonic blocking (both second and fifth harmonics).

Additionally, stability checks for through fault conditions will be explored, providing insights into verifying the stability of the differential protection settings during such scenarios.

By the end of this article, readers will gain a comprehensive understanding of the step-by-step process involved in calculating the differential relay settings for the GE P642 protection relay. This knowledge will enable engineers and protection specialists to optimize the relay’s performance, ensuring efficient and reliable differential protection for transformers.

So, let’s embark on this informative journey, exploring the intricacies of calculating the GE P642 relay’s settings for differential protection configuration.

Table of Contents:

  1. Data collection for calculating GE P642 relay settings in differential protection configuration
  2. Calculation of transformer full load currents
  3. Variations in current ratios due to tap changer windings
  4. Transformer through fault current calculation
  5. Calculations of CT secondary current corresponding HV and LV
  6. Ratio correction factor calculations
  7. Calculations of HV & LV current at extreme tap positions
  8. Bias Current in differential protection
  9. Calculations of differential pickup current
  10. Differential slope calculations
  11. Current transformer supervision (CTS)
  12. High-set differential protection function
  13. Second harmonic blocking [Ih2%>)
  14. Fifth harmonic blocking (Ih5%>)
  15. Stability checks for through fault condition
  16. Concluding the Final Setting of 87T (protection relay P642)
  17. BONUS! Differential relay settings paper and presentations (PDF)

1. Data Collection For Relay Settings

Calculating GE P642 Relay Settings in Differential Protection Configuration

The initial phase of configuring the settings for the differential protection relay involves gathering data, and to accomplish this, we have opted to use a 100 MVA Power Transformer. The selected transformer corresponds to the real transformer installed in the field, and the settings are computed specifically for the GE P642 Differential Protection Relay.

Table 1 – Transformer and CT details

No.DescriptionRating
1Transformer rating100 MVA
2HV side voltage132 kV
3LV side voltage33 kV
4Vector groupYNd1
5Impedance12.5 %
6HV side current437.4 A
7LV side current1749.5 A
8Tap range±10%
9Primary CT ratio500/1 A
10Secondary CT ratio1800/1 A

Go back to Content Table ↑


2. Calculation of Transformer Full Load Currents

After the data collection stage, the next step involves calculating the full load currents at the high voltage (HV) and low voltage (LV) sides of the transformers. The following formula will be utilized to compute the full load current of the transformers at both HV and LV sides:

S = √ 3 V × I

Here, S is transnformer rating, V is voltage and I is current.

To calculate the full load current at the HV side, utilize the HV voltage at the nominal tap. For determining the full load current at the LV side, consider the LV rated voltage of the transformer. Normal tap or nominal tap is the tap position at transformer tap changer at which, when rated voltage is applied the rated voltage will be received at transformer secondary side.

For example if system HV rated voltage is 132kV and actual voltage is also 132kV then when transformer is at the normal tap then rated 33kV voltage will be available at LV side.

Figure 1 – Transformer taps

Transformer taps
Figure 1 – Transformer taps

Normal tap is also referred to as the 100% tap, Taps located above this point are referred to as positive taps, while those positioned below it are known as negative taps.

Calculations of HV Full Load Amperes (HV FLA):

HV full load current can be calculated as:S = 100MVA
HV voltage = 132kV
HV full load current = IHV
Hence, Transformer HV FLA at nominal tap:P / √ 3 V =
100000 / (√3×132) = 437.4 A
HV Full Load Current = 437.4 Amperes

Calculations of LV Full Load Amperes (LV FLA):

LV full load current can be calculated as:S = 100MVA
LV voltage = 33 kV
LV full load current = ILV
Hence, Transformer LV FLA at nominal tap:P / √ 3 V =
100000 /(√3×33) = 1749.5 A
LV Full Load Current = 1749.5 Amperes

Here, it can be seen that there is a difference between HV and LV current at the given MVA rating of the transformers. A transformer may change the voltage or current levels but the apparent power will remain the same for HV and LV windings.

The differential protection relays are responsible for ensuring that the current levels on both the high voltage and low voltage sides of the transformer are equalized. The earlier generations of relays were electromagnetic relays, and as a result, matching CTs were installed to compensate for the difference in current.

However, modern relays are numerical relays with the capability of a microprocessor, and as a result, they are able to compensate the ratio internally; all that is required is to configure the transformer and the current transformer.

Go back to Content Table ↑


3. Variations in current ratios due to tap changer windings

Another impact that needs to be considered while doing setting calculations is to compensate for the error introduced in the current ratio due to tap changer winding. Because of tap changer windings, the turn ratio of the transformer does not remain the same and hence the current ratio will also differ.

That means that even if we define the ratio compensation inside the relay, there still will be the spill current/differential current when transformer tap is changed from normal tap position to minus or plus taps.

We will calculate the voltage values at extreme tap positions.

Membership Upgrade Required

This content is not available in your premium membership plan. Please upgrade your plan in order to access this content. You can choose an annually based Basic, Pro, or Enterprise membership plan. Subscribe and enjoy studying specialized technical articles, online video courses, electrical engineering guides, and papers.

With EEP’s premium membership, you get additional essence that enhances your knowledge and experience in low- medium- and high-voltage engineering fields.

Did you know?Save 50% on all video courses by purchasing Enterprise plan.

Upgrade

Already a member? Log in here

Premium Membership

Get access to premium HV/MV/LV technical articles, electrical engineering guides, research studies and much more! It helps you to shape up your technical skills in your everyday life as an electrical engineer.
More Information
author-pic

Muhammad Kashif

Muhammad Kashif Shamshad is an Electrical Engineer and has more than 17 years of experience in operation & maintenance, erection, testing project management, consultancy, supervision, and commissioning of Power Plant, GIS, and AIS high voltage substations ranging up to 500 kV HVAC & ±660kV HVDC more than ten years experience is with Siemens Saudi Arabia. He completed over 20 high voltage substation projects, Operation & Maintenance of Substations & Power plants in Pakistan and Saudi Arabia for different electric utilities, including Saudi Electricity Company (SEC), Saudi Aramco, SABIC, Marafiq, National Transmission & Dispatch Company (NTDC), WAPDA, and K-Electric. Also, he led testing and commissioning teams to implement electrical infrastructure projects for many industrial clients (Steel, Petrochemical, etc.) in Pakistan and Saudi Arabia.

Leave a Comment

Tell us what you're thinking. We care about your opinion! Please keep in mind that comments are moderated and rel="nofollow" is in use. So, please do not use a spammy keyword or a domain as your name, or it will be deleted. Let's have a professional and meaningful conversation instead. Thanks for dropping by!

sixty four  ⁄  sixteen  =  

Learn How to Design Power Systems

Learn to design LV/MV/HV power systems through professional video courses. Lifetime access. Enjoy learning!

EEP Hand-Crafted Video Courses

Check more than a hundred hand-crafted video courses and learn from experienced engineers. Lifetime access included.
EEP Academy Courses - A hand crafted cutting-edge electrical engineering knowledge