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# How Power Factor Corection Works

## Understanding Power Factor

As with any equipment, an electrical system handles its job to some degree of efficiency ranging from poor to excellent. The measure of electrical efficiency is known as Power Factor. The motors and other inductive equipment in a plant require two kinds of electric power.

One type is working power, measured by the kilowatt (kW). This is what actually powers the equipment and performs useful work. Secondly, inductive equipment needs magnetizing power to produce the flux necessary for the operation of inductive devices. The unit of measurement of magnetizing or reactive power is the kilovar (kVAR).

The working power (kW) and reactive power (kVAR) together make up apparent power which is measured in kilovoltamperes (kVA).

Most AC power systems require both kW (kilowatts) and kVAR (kilovars). Capacitors installed near the loads in a plant are the most economical and efficient way of supplying these kilovars. Low voltage capacitors are traditionally a high reliability maintenance-free device.

On the spot delivery of magnetizing current provided by capacitors means that kilovars do not have to be sent all the way from the utility generator to you. This relieves both you and your utility of the cost of carrying this extra kilovar load. The utility charges you for this reactive power in the form of a direct, or indirect power factor penalty charge.

In addition, you’ll gain system capacity, improve voltage and reduce your power losses.

1. Vishwajeet Kumar thakur
Nov 07, 2017

Sir
I have a motor 3hp. My average power factor is.63 to .65, but suddenly its shows .04 is it possible or not.
Or my meter is correct or not

Aug 08, 2017

Thank you and the EE team, I have gotten really useful guidance and information.

3. Edvard
Aug 03, 2017

4. Ben Macey Australia
Aug 03, 2017

5. Ma. Rizzalyn Pabito
May 30, 2017

6. Emin M
Feb 20, 2017

7. JosÃ¨ Severino Queiroz
Feb 02, 2017

Excuse me ! Is there any diference between the theorical calculation and mesured result? About power factor and reactive energie?

8. Thiagarajan
Sep 26, 2016

sir, i have a doubt,is anycalculated time to reach the desired power factor for example a load of 630 kw and capacitor bank is 575 kvar present p.f is 0.13 required p.f is 0.98 at what time the p.f will reach.
regards,
thiagarajan

9. waleed
Apr 16, 2015

So Sorry I forgot to thank you for the interesting information

10. waleed
Apr 16, 2015

I think you can provide us with new books of electronics and electricity

11. Raffy F. Yanuario
Oct 11, 2014

very good info…

12. MODUGULA
Mar 06, 2013

it’s fantastic