## Calculation of the energy savings

**In order to calculate power factor correction for your installation, your should follow the steps below:**

**Step 1** **– Calculate Actual Load (kW)**

(Load) Power **kW** = Volts **V** x **âˆš3** x Current **I** x Power factor **Pf**

**Step 2 – Calculate Required Power Factor Correction (kVAr)**

Power Factor Correction **kVAr** = Power **kW** (**TanÎ¦i – TanÎ¦d**)

**Î¦i**Â = Cos^{-1} Initial Power Factor Pf

**Î¦d**Â = Cos^{-1}Â Required Power Factor Pf

**Step 3** **– Calculate Actual Power Factor Correction [kAVrl**

Actual Power Factor Correction Pf = Cos (**Tan ^{-1}**Â (

**TanÎ¦i**–

**Correction kVAr**/

**Power kW**))

Typical Power Factor Correction available in multiples of 25kVAR’s, for further details please Contact Blakley Electrics Technical Department.

**At the end of the spreadsheet you will get the calculation of the energy savings for above power factor correction.**

- Initial Current (Amps)
- Original Load (kVA)
- Corrected Current (Amps)
- Corrected Load (kVA)
- Reduction in Current (Amps)
- Reduction in Load (kVA)
- Annual CO2 Savings ( kg C02)

Software: | Power Factor Correction Calculation |

Version: | – |

Developer: | Blakley Electrics |

Size: | 163 kB |

Price: | Free |

Download: | Right here | Video Courses | Membership | Download Updates |

Hi, Share calculation

Thanks for sharing such kind useful article.

I am an electrical engineer In Nagpur good information i got from your site.

thanks a lot.

Hello sir’

im working as a electrical design engineer

kindly please clear my doubts

1) how to find the incomer current rating for APFCR panel ?

2) how to find the breaker current rating for the 25kvar & 50kvar capacitor ?

please give the answer??

and i refer this method its right or wrong??

Kvar= 1.73*V*I*Sin$ ($ IS INSTESD OF PHASE ANGLE PHI)

so I= kVAR/1.73*V*SIN$

IN A PURELY CAPACITIVE CIRCUIT $ IS 90 DEGREE

SO TERM SIN 90 = 1

HENCE WE CAN CALCULATE CAPACITOR CURRENT BY kVAR/1.73*V

Sir, please tell me formula for improve power factor.. And which type of problems occur in industry’s when we maintain leading power factor

Excelente portal, gracias por las publicaciones.

Hello Friends,

I want to learm Electrical Engineering. Where i start because lot of topics in the electrical. Please guide me.

mail id : [email protected]

sir i am working as a technician in private industry, plant is running with load about 900 kva how much capacitance we should need to connect, what kind of problems arise when we are connect capacitance more than required value kindly send the answer to my mail id

thanking you sir.

You will spend more capacitors than necessary, I presume thati It is expensive. You will loose money. And if there were a much more capacitance, you will need more KVAr again, but now capacitive.

sir, give me formula for improve power factor. how can i get which capacitor will improve power fsctor

thanks a lot for sharing of important electrical information .I thinks this side is very helpful for EEE ,MEE,

I am an electrical engineer graduated from s.j.c.e mysore – india .

good information i got from your site.

thanks a lot.

The information I have got are very useful and are of great importance to the problem that I was working on.

How to find out the wire size for connecting to PFI unit?? We have an 800kva substation.

Thanks for sharing such nice information

Thanks for sharing such nice information…. but i want to add some basic formulas

fromHow to Calculate the Suitable Capacitor Size in Farads & kVAR for Power factor Improvement (Easiest way ever)