## Power Factor correction using static capacitor

**Calculation formulas as follows:**

**Q**= I_{1}_{losses}+ Cu_{losses}**Q**= P_{2}_{kW}· (Tanφ_{1}– Tanφ_{2})**I**= 2% · S_{losses}_{tr}**Cu**= U_{losses}_{SC}% · S_{tr}**Q**= Q_{1}+ Q_{2}

**Where:**

**Q**= Reactive power to be compensated at the terminals of a transformer due to no load and load losses._{1}**Q**= Reactive power to be compensated due to total reactive components of lighting, power and mechanical loads._{2}**Q**= Overall reactive power to be compensated to achieve target power factor.**I**= Transformer no load losses =_{losses}**Iron core losses**.**Cu**= Transformer load losses =_{losses}**Copper losses**.**S**= Transformer rating (KVA)._{tr}**P**= Maximum demand load on the Main distribution board (kW).**φ**= Inverse cosine of power factor before compensation._{1}**φ**= Inverse cosine of target power factor._{2}**U**= Short circuit percentage impedance voltage of the transformer._{sc}%

**Power Factor Values assumptions before compensation:**

- For lighting outlets =
**0.96** - For power outlets and receptacles =
**0.8** - For motors =
**0.8**

Inputs =Transformer size + Transformer type + kVA Max. demand load for the whole system + PF before compensation + Target value of PF.

Outputs =Reactive power to be compensated at the terminals of a transformer due to no load and load losses.

**Reactive power to be compensated**due to total reactive components of lighting, power and mechanical loads**Overall reactive power to be compensated**to achieve target power factor + circuit breaker size required to protect the capacitor bank.

Software: |
Power factor correction calculations for power system – MS Excel Spreadsheet |

Version: |
– |

Developer: |
Mahmoud Salama |

Size: |
126 KB |

Price: |
FREE |

Download: |
Right here | Get Download Updates | Get Premium Membership |

A 1000-KVA transformer is loaded to 850 KVA at a power factor of 0.82

lag. Calculate the leading kVAR necessary to correct the power factor to 0.95 lag.

If the transformer has a rated conductor loss equal to 1.0% of the transformer rating,

calculate the energy saved assuming 24-hour operation at the operating load.

very nice

hi, I seeking standard that report desirable Power Factor in distribution network.

is it possible anyone guide me.

sir request 1kva transformer design and calculation winding bobbin size select

testing report valve with reference range

send me sir pdf

Good topics,

Thanks so much.

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