## Transformer Losses

Transformers have two major components that drive losses: **the core** and **the coils**. The typical core is an assembly of laminated steel, and core losses are mostly related to magnetizing (energizing) the core.

These losses, also known as **no-load losses**, are present all the time the transformer is powered on â€“ regardless of whether there is any load or not.

Core losses are roughly constant from no-load to full-load when feeding linear loads. They represent a continuous cost, 24 hours/day, for the 25-year or more life of the transformer.

### Formulas in spreadsheet

**HV Full load current**= VA / (1.732 Â·Â Volt)**LV Full load current**= VA / (1.732 Â·Â Volt)**HV Side I**= IÂ²R Â·Â 1.5^{2}R losses**LV Side IÂ²R losses**= IÂ²R Â·Â 0.5 Â·Â 3**Total IÂ² R lossses at Amb. temp**= Hv losses + Lv losses**Total Stray losses at Amb. temp**= Measured losses – IÂ²R losses**IÂ²R lossses at 75Â° C temp**= ((225 + 75) Â·Â losses) / (225 + Amb. temp) .**Stray losses at 75Â° C temp**=((225 + Amb. temp)(Stray losses at Amb. temp)) / 300**Total Full load losses at 75Â° C**= IÂ²R losses at 75Â° C + Stray losses at 75Â° C**Total Impedance at amb. temp**= (Imp. voltage Â·Â 1.732) / Full load current**Total Resistance at amb. temp**= IÂ²R losses / IÂ²**Total Reactance (X)**= SQRT (ImpedanceÂ² – ResistanceÂ²)**Resistance at 75Â° C**= (300 Â·Â resistance at amb ) / (225 + Amb. temp)**Impedance at 75Â° C**= SQRT (RÂ² at 75Â° C + XÂ²)**Percentage Impedance**= (Z at 75Â° C Â·Â I Â·Â 100)/V1**Percentage Resistance**= ( R 75Â° C Â·Â I Â·Â 100)/V1**Percentage Reactance**= (X Â·Â I Â·Â 100) / V**Regulation at Unity P.F.**= (%R cosÃ¸ + %XsinÃ¸)**Regulation at 0.8 P.F.**= (%R cosÃ¸ + %XsinÃ¸) + 1/200(%R sinÃ¸ – %XcosÃ¸)^{2}

#### Efficiency at Unity P.F

**At 125 % of Transformer Loading**= (kVAÂ Â·Â 1.25 Â·Â 100)/((kVAÂ Â·Â 1.25)+(IÂ²R losses Â·Â 1.25Â²)+(No Load Losses))

#### Efficiency at 0.8 P.F

**At 125 % of Transformer Loading**= (kVAÂ Â·Â 1.25 Â·Â P.F. Â·Â 100)/((kVA Â· P.F.Â Â·Â 1.25)+(IÂ²R losses Â·Â 1.25Â²)+(No Load Losses))

## Contribution to transformer losses

**Load level varies widely, with some installations running very heavily loaded and others more lightly loaded.**

This difference substantially impacts actual losses incurred. Unfortunately, there is a small body of field data available, driven by the factors such as a lack of awareness of the cost of the losses, and the cost of gathering detailed data from a reasonable number of individual transformers.

**load level**,

**load profile**, and

**core and coil construction**.

Since there are a wide variety of transformers on the market serving different purposes, and available from different manufacturers, actual losses incurred in the field will vary substantially from installation to installation.

Software: | Spreadsheet for Transformer Losses Calculation |

Version: | 10.06.2013 |

Developer: | Jignesh Parmar |

Size: | 36 Kb |

Price: | Free |

Download: | Right here | Get Download Updates | Get More With Premium Membership |

Sir, coul you explain temperature gradient calculation of HV and LV winding , if temperature rise 40/50

Please tell how to calculate no load losses of transformer.

Tell me how to get transformer copper loss

I have no load losses n total power loss

Dear sir,

Dry type and oil type transformer losses how to calculate.

specs of hi pot tester from 10 to 35kv?

How can I calculate no load losses and load losses of power trafo when I have total losses of trafo available only?

Great work, keep it up ^_^

On this formula: Total Stray losses at Amb. temp = Measured losses â€“ IÂ²R losses, if I measured V= 384, I= 20 and W= 1015, for a 24MVA, 231200V (on tap 1), how do I relate the measured power into the equivalent input power which I can use in the formula?

The spreadsheet for transformer losses calculations is a good work

how do find out the value of resistance in hv and lv side

please review cell H33, i think efficiency should not be highest at 125%

Dear all,

How can I get the value 1.5 in ” HV Side I2R losses = IÂ²R Â· 1.5″ and 0.5*3 in

” LV Side IÂ²R losses = IÂ²R Â· 0.5 Â· 3″ .

Thank you in advanced.

Dear all,

What are the values 1.5 in HV and 0.5*0.3 and LV ?

HV Side I2R losses = IÂ²R Â· 1.5

LV Side IÂ²R losses = IÂ²R Â· 0.5 Â· 3

Thank you in advanced.

Dear sir,

For finding i^2R losses on hv side =I^2R.1.5

What does 1.5 means

Dear Venjateswar,

Did you find any answer for this question ?

Best regards,

Hello!

what is V1 and V for the percentage impedance and reactance?

Thanks!

The V1 is the voltage that, applied to the HV side of the Tx whose voltage rating is V, shall circulate the rated current on the LV side of the Tx with it’s terminal short circuited. This voltage is expressed as a %age.

Z%=(V1/V)*100.

Is the measured loss a physically measured value? Is there a way of estimating this number based on the transformer size?

Edvard / Jignesh

well done gents this is practical and useful I like it!.

Here is a suggestion for you ready reckoner spread sheets for estimating:

overhead power lines e.g. 415V AC distance covered number of bends and calculate the number of posts, cross arms, insulators, conductor sizes, tension, weight of the conductors….

same for 22kV or 33kv or underground with approximate schedules of rates so I can enter local steel costs ideal pole spacing typical sag heights….

can you provide spreadsheet for transformer losses calculation of 1000kva

Can’t you use this spreadsheet? Just edit field rated power in kVA.

How can we convert this losses to thermal losses?

They are thermal origin. Find out more here:

https://electrical-engineering-portal.com/transformer-heat-copper-and-iron-losses

EEP provides much more information about any given electrical article which is guide line for technical people.

Thank you Ahmad!