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Home / Technical Articles / The essentials of electrical systems in cement plants

Power supply & distribution in cement plants

Many young engineers consider cement plants pretty complicated because of their weird technology. The reason probably lies in the fact that you cannot understand all those technologies unless you worked in such a plant and saw all processes from scratch. However, this article will try to bring down a few essential production steps in the cement plant, as well as the power supply and distribution in cement plants.

The essentials of electrical systems in cement plants
The essentials of electrical systems in cement plants (on photo: Low voltage motor control centres type 'Sivacon S8'; credit: elsta.pl)

Before we dive into details, note that this article assumes that you are already familiar with the basic terms of cement plant equipment and process. But, let’s first describe how the cement plant works after all.

So, let’s describe the six main operational phases:

Cement plant production and operational phases
Figure 1 – Cement plant production and operational phases (click to expand)

Step #1

The most important raw materials for making cement are limestone, clay and marl. These are extracted from quarries by blasting or by ripping using heavy machinery. Wheel loaders and dumper trucks transport the raw materials to the crushing installations.

There the rock is broken down to roughly the size used in road metalling.


Step #2

The crushed material is transported into the raw material storage of the cement plant by conveyor-belts, cableways or railways and also in exceptional cases with trucks. Once there it is stored in blending beds and homogenised.


Step #3

The desired raw mix of crushed raw material and the additional components required for the type of cement, e.g. silica sand and iron ore, is prepared using metering devices.

Roller grinding mills and ball mills grind the mixture to a fine powder at the same time as drying it, before it is conveyed to the raw meal silos for further homogenisation.

Step #4

The burning of the raw meal at approx. 1,450°C is carried out in Lepol or preheater kilns that work by varying methods, the main difference being in the preparation and preheating of the kiln feed.

By chemical conversion, a process known as sintering, a new product is formed: clinker.


Step #5

After burning, the clinker is cooled down and stored in clinker silos. From there the clinker is conveyed to ball mills or roller presses, in which it is ground down to very fine cement, with the addition of gypsum and anhydrite, as well as other additives, depending on the use to which the cement is to be put.


Step #6

The finished cement is stored in separate silos, depending on type and strength class. From there it is mainly loaded in bulk form from terminals onto rail or road vehicles as well as onto ships.

Only a small proportion of the cement reaches the customer in the form of bags that have been filled by rotary packers and stacked by automatic palletising systems.

Table of contents:

  1. Power Distribution Design For Cement Plant
  2. Voltage and Frequency
  3. Power Distribution Grids Macro Scale
  4. Generation of Power
    1. Thermal Power Stations
    2. Captive Power Plants
  5. Distribution System Within the Plant
    1. Ring Mains Within the Plant
    2. Medium Voltage Drives
    3. Variable Speed Drives (VSD)
  6. MV and LV Drives in a Section
  7. Synchronization of Grid and Captive Power
  8. Power Factor
    1. Current Carried and Power Factor
    2. Correction of Power Factor
  9. Designing Power Distribution System
    1. Working Requirements of Power Step by Step
    2. Margins to be Provided
    3. Load Factor
    4. Margins for Substation (Capacity and Expansion)
    5. Selecting Transformers
  10. Electrical Power Tariff
    1. Maximum Demand

1. Power distribution design for cement plant

Power distribution system of a cement plant begins with the substation of the grid where power is received and ends with individual drives and points of usage. It is a large network consisting of elements like: distribution transformers, MV/LV control panels, individual distribution switchboards and motor control centres (MCCs), switchgears for safety, regulation and metering of power used at various points, motors and their controlgear, power and control cables, lighting, earthing and other components of the system.

Design of the power distribution system is a specialised job and should therefore be entrusted to the specialists. In this technical article electrical systems in cement plant will be touched upon.

All machines are driven by electric motors. Majority of the motors are 400- 440 volts. A selected few motors of higher ratings are MV motors with 3300, or 6600 or 11000 volts. Most motors are fixed speed and unidirectional motors. Motors for kilns and coolers, feeders, and some fans are variable speed motors.

Variable speed motors can be either AC or DC with ratings ranging from fractional kws, for motors for dampers, valves etc., to several hundred kws for motors for fans. All these motors are to be supplied with electric power at voltage and frequency and type of circuit for which they are designed.

Cement plant
Figure 2 – Cement plant

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2. Voltage and Frequency

Depending on the country, frequency of power supply can be 50 or 60 cycles. Voltage of transmission could be as high as 222 KV or 132 KV for large capacities and 66 KV, 33 KV or 11 KV down the line depending on MVA capacity of the substation.

The voltage of generation itself would be say 6.6 KV. It is stepped up for transmission; longer the distance over which power is to be transmitted higher the voltage oftransmission to minimize losses in transit.

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3. Power Distribution Grids Macro Scale

The whole system of distribution of power can be shown pictorially as a ‘grid‘ linking the several generating stations in a State. Grid ensures that power is assured to all consumers, even to remotest customers at all times. See Figure 3. Thus customers ‘a‘ and ‘b‘ can draw power from generating station 1, 2 or 3.

Grid within one State is connected to grids in another State and also to ‘national grid’.

Electrical power distribution system of a cement plant - Macroscale
Figure 3 – Electrical power distribution system of a cement plant – Macroscale

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4. Generation of Power

Bulk of the power is generated by Country Electricity Boards. It can be thermal power using coal as fuel; team is generated in boilers and drives turbines which in turn drive alternators or generators. Power is also generated in hydroelectric power stations by using water power. A balanced proportioning of generation between thermal and hydro power ensures availability of power in all circumstances in all seasons of the year.

Hydro power is obtained from water, which in turn depends on seasonal rain fall. When rainfall is scanty, quantity of water collected is affected and power generation is reduced. Hydro power generation is thus close to the source or storage of water.

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4.1 Thermal Power Stations

Thermal power stations based on generating steam in boilers by burning coal depend on regular supply of coal. This coal can come from near or from far. Its supply may be affected by strikes in collieries or by bottlenecks in transport system, and sometimes also by fluctuations in the quality of coal supplied.

Automatic bus transfer scheme in thermal and nuclear power stations

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4.2 Captive Power Plants

Generally, cement plants should install its own Power Plant to meet at least 40% of their requirements. A large number of captive power plants installed by cement industry have been d.g. sets; many large cement plants have however opted for coal based thermal power plants.

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5. Distribution System Within the Plant

In a cement plant also there is a ‘mini grid‘ receiving power from main electricity grid and also from plant’s captive power plant. They have to work simultaneously and hence should be ‘synchronized’ when working in parallel, i.e., the voltage, frequency and phase must match.

Alternatively, captive power is used only to supply power to specific sections like kiln and one of the two major mills.

However, the present trend is to size captive power station large enough and to synchronize captive power with grid power. There was a time when Cement Plants found it cheaper to use their own Power as compared to grid power. In recent times however prices of both light and heavy oils have shot down and hence this situation may change again.

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5.1 Ring Mains Within the Plant

The plant has what is known as a ‘ring main‘ which supplies grid power to load centers within the plant. If the captive power plant is large enough there can be two ring mains in parallel.

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5.2 Medium Voltage Drives

Normally, drives of following machinery would be medium voltage motors:

  1. Main crusher
  2. Raw Mill
  3. Preheater fan
  4. Coal Mill
  5. Cement Mill

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5.3 Variable Speed Drives (VSD)

In the last 25 years, variable speed drives (VSD) have been used more frequently in the cement industry. The main reason was to save energy in the production process. Generally speaking, variable speed motors would be used for electric motors listed in Table 1 below.

Table 1 – Variable Speed Drives

No.Motor for:DCAC
1Crusher Feeder
Reclaimer drives
2Raw Mill Feeders
3Raw Mill air separator
4Preheater Fan
5Prefeeders and Feeders for kiln Feed
6Kiln
7Grate Cooler grates
8Cooler vent fan
9Cooling air fans for at least first two compartments
10Coal mill feeder
11Feeders and prefeeders for fine coal for kiln and calciner
12Feeders for cement mill
13Separator for cement mill
14Packing machine

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6. MV and LV Drives in a Section

Thus some sections will have only LV supply and others both MV and LV supply and also DC drives. One option is to step down voltage from grid voltage for the total plant in one place and lead HT lines from it to respective sections in which MV motors are used. See Figure 4.

Power distribution - with grid and diesel generator set in parallel
Figure 4 – Power distribution – with grid and diesel generator set in parallel

This arrangement required long 6.6 KV cables to various sections. Another option is to locate transformers near load centers i.e., near mills and kiln. See Figures 5 and 6.

Both arrangements have their own positive and negative points. Main objective should be to achieve continuity of supply of power of right quality (fluctuations in voltage and frequency and phase should be within permissible limits) and flexibility (supply can be either from grid or captive power) without interruption.

132/6.6 kV transformers near load centers
Figure 5 – 132/6.6 kV transformers near load centers
Distribution of LV power at 415 Volts
Figure 6 – Distribution of LV power at 415 Volts

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7. Synchronization of Grid and Captive Power

Even when parallel busbar system or ring system is not used, the grid supply and captive supply must synchronize and work in parallel or individually without disrupting power supply to any section of the plant.

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8. Power Factor

Another important aspect is that of power factor. It’s important to know that:

  1. Induction motors work at varying lagging power factors depending on load.
  2. D.C. motors have unity p.f. on d.c. side.
  3. In case of synchronous induction motors, power factors can be altered between leading and lagging.

Useful Power:

Power factor as close to unity between 0.95 to 0.90 lagging is desirable to get maximum from power purchased from the grid station. Lower the power factor, less is the useful energy available and greater the losses.

When power factor is unity, useful power available is: V × A × 1/1000 = KVA = KW. This means that if power factor is say 0.80, useful power available is: V × A × 0.8/1000 = 0.8 VA KW

Power bills are based on kWh consumed and charges for maximum demand are on KVA.

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8.1 Current Carried and Power Factor

Current required to be carried by cables varies according to power factor (PF). See Table 2.

Table 2 – Ratings of motors

Power Factor10kW15kW25kW50kW100kW
Current in Amps
 113.920.934.869.5139
 0.915.423.138.577154
 0.817.426.143.587174

Say total load of above motors is 200 KW; total current at unity power factor would be 278 amps. If power factor were 0.85, the current would be 328 amps. All cables would draw correspondingly higher current right up to the substation.

It is therefore, important to correct power factor at levels of individual drives and also main power distribution panels.

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8.2 Correction of Power Factor

Generally, correction of power factor is done by:

  1. Using individual capacitors for motors and by using ‘capacitor banks‘ in total sections.
  2. Using synchronous induction motors to correct overall power factor by running them on leading power factor.
Let total load be 10000 KW and let there be two (2) synchronous induction motors each of 2000 KW rating; Other load is then 6000 KW. Total load consists of: 6000 KW of 0.8 lagging PF and 4000 KW of 0.95 leading PF.

Overall power factor can be improved to ~ 0.96 lagging. Current will reduce by 17 %. See Figure 7. Total power factor for the plant can be worked out in this fashion. If synchronous induction motors are not available, capacitor banks of suitable ratings and voltage are added in the circuit to obtain desired improved PF.

Effect of power factor
Figure 7 – Effect of power factor

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9. Designing Power Distribution System

One of the first things to be done in designing the distribution system is to work out the power to be drawn from the grid for the plant. This can be drawn on a broad basis starting from overall power consumption of similar cement plants.

For example if similar plants are consuming 95-100 kWh/ton of cement, it may be assumed that the new plant will also consume the same amount and total power to be drawn calculated as shown in subsequent paragraphs.

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9.1 Working Requirements of Power Step by Step

Alternately the exercise may be done step by step. For this the first step is to arrive at departmental power consumption of each section in terms of power/ton of material handled. Then ‘convert’ it into clinker and then into power per ton of cement.

Take example of Raw mill Department.

  • List all drives with their ratings.
  • List power drawn at rated capacity.
  • Work out for total section.

See Table 3.

Table 3 – Selecting working number of motors

Number of motorsDrive rating [kW]Power drawn as % of drive ratingTotal actual power drawn [kW]
10.83.2
50.812
600.848
20000.91800
5000.85425
2000.8160
10×200.8160
Total:29802608

  • Total connected load is 2979 say 2980 kW
  • Let material ground be 3000 tons in 20 hours.
  • Therefore Tons/hour = 3000/20 = 150 tph.
  • Average kWh/ton of material ground = 2608/150 = 174 kWh
  • Power consumption per ton of clinker with a conversion ratio for consumption 1.55 : 1 = 17.4 x 1.55 = 27 kWh/ton
  • Using 4% gypsum – 1 ton clinker = 1.04 tons of cement
  • Therefore power consumption per ton of cement = ~26.0 kWh

In this manner list all sections of the plant. See Table 4.

Table 4 – Power consumption for whole plant

ConsumptionUnit/Tons Of material kWhMaterial Conversion factorUnits/Ton
clinker
kWh
Units/Ton
cement
kWh
Quarrying0.5210.96
Crushing Raw Material1.51.53.252.16
Grinding161.55 24.823.85
Blending21.553.12.98
Kiln Feed, Kiln Calciner0.51.650.8250.79
Preheater, Cooler2512524
Coal Mill300.154.54.33
Cement Mill35135
Packing212
Water supply Lighting – Factory & Colony Other Utilities & Losses5 all together
Units:101.07
Say:101.00

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9.2 Margins to be Provided

For working out requirements of power to be drawn, it is desirable to add:

  • 5-10% on actual consumption.
  • Assume 10 %
  • Design margin of 10% on rated capacity
  • Therefore, specific power consumption = 111 kWh/ton
  • Let rated capacity of plant = 3000 ton/day
  • Hourly = 125 ton/hour
  • With design margin = 137.5 ton/hour
  • Therefore kw = 111 × 137.5 = 15260 KW
  • This needs to be converted into KVA.

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9.3 Load Factor

For conversion power factor and load factors are to be taken into account. Power factor has been dealt with above. Though it would be maintained at 0.95, for working out power to be procured, it may be taken as 0.9. Load factor is a usage factor; all machines do not run for all the 24 hours and at a constant load.

Peak loads occur at different times in different sections. To obtain required capacity in spite of fluctuations, higher capacity is needed to be installed. See Figure 8.

For cement plants where most sections work in three shifts, it is customary to take load factor as 80%. Thus if 15260 KW are required and load factor is 80%, rating to be installed would be 15260/0.8 = 19080 KW. Power required to be obtained in KVA at 0.9 PF = 21200 KVA.

Load Factor
Figure 8 – Load Factor in a cement plant

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9.4 Margins for Substation (Capacity and Expansion)

The substation capacity should allow for some margin for additions etc., that are not foreseen today. Therefore for the first phase, electrical demand would be fixed at with say a 25% margin. That would be 21000 × 1.25 = 26500 KVA say 26.5 MVA.

If duplication is imminent, substation should be designed for double capacity, i.e., incoming line should have capacity to deliver 53 MVA. In substation, transformers can be added phase-wise.

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9.5 Selecting Transformers

In selecting transformers, it is a good idea to select two transformers in parallel rather than one. Transformers are generally loaded up to 70 to 80 % of their rating. In above case total load = 26.5 MVA. Total rating of transformer would be 26.5/0.7 = 38 MVA. It would be preferable to select two transformers of 19 MVA each or even 20 MVA each.

If a ring system is used, there will be more than two transformers located near load centers. Each of these transformers should also be loaded to 70% capacity in actual operation.

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10. Electrical Power Tariff

Electrical tariff is in two/three parts :

  1. Energy consumption in $/kWh.
  2. Maximum demand costs in $/KVA/month.
  3. Any other duties as may be in force in each country from time to time.

Power is measured by energy meters installed by Grid Electricity Board in their Substation. Maximum demand is also recorded there. Energy meters must of course be calibrated periodically.

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10.1 Maximum Demand

Many a time sudden overloads or simultaneous working of all sections can push up the maximum demand and power drawn will exceed contracted maximum demand. In such a case, fine is to be paid. In times of power cuts, contracted demand would not be utilized.

In general the plant would opt out to be penalized for not using the contracted demand rather than reduce it. In times of scarcity of power, National Electricity Board come down heavily on unutilized maximum demand and may reduce the contracted demand.

The impact of tariff on account of maximum demand however is generally about 10% of direct costs of energy.

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Sources:

  1. Handbook for designing cement plants by S. P. Deolalkar
  2. How Cement Is Made by HeidelbergCement
  3. Sucess in Vietnam, Total plant solution for the Cam Pha cement plant by ABB

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Edvard Csanyi

Electrical engineer, programmer and founder of EEP. Highly specialized for design of LV/MV switchgears and LV high power busbar trunking (<6300A) in power substations, commercial buildings and industry facilities. Professional in AutoCAD programming.

3 Comments


  1. Dr A K Chatterjee
    Oct 05, 2020

    Very neatly presented


  2. venky
    Sep 23, 2020

    thank you


  3. Umesh Panda
    Sep 16, 2020

    Dear Sir,
    Your thesis was very helpfull. Also required more deep study.

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