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# The principles of differential protection you MUST understand

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## Differential protection

Although nowadays differential protection is achieved numerically, in order to understand the principles of differential protection it is useful to analyze the ubiquitous electromechanical relay. Figure 1 shows a simple differential protection scheme, also known as a Merz-Price scheme.

In this simple scheme, we can assume that under normal operating conditions, the current entering into the piece of equipment under protection is equal (or in the case of a transformer, proportional) to its exiting current. In this example, we will assume that the entry and exit currents are equal.

A circuit breaker on either side of the equipment under protection is controlled by an overcurrent relay.

Current transformers of identical types and turns ratio are installed on either side of the equipment. These current transformers induce identical secondary currents because their primary currents are identical and they have the same turns ratio.

By simple inspection of the diagram, it is clear to see that under these circumstances no spill current will flow through the relay, therefore no trip signals will be generated.

### …and when the fault occurs

Consider a fault internal to the equipment. A large current would flow through the fault, thus the current exiting the equipment would rapidly reduce resulting in a reduced secondary current in CT B. This would cause a current to flow through the relay, which would be of a magnitude sufficient to trip the circuit breakers.

Now consider an external fault at F as shown in Figure 2.

You can see that in this case, the current exiting the equipment, albeit large, is still the same as the current entering it, therefore the relay will not trip. This is exactly as how we want it, because faults external to the equipment are in a different protection zone and are protected within another scheme.

If the equipment to be protected is a busbar, or generator winding, for instance, it is clear that the exit current is the same as the entry current. If, however, the equipment is a transformer where the turns ratio is not equal to one, the current entering will be different from the current exiting.

In this case, the current transformers must be balanced with an equivalent turns ratio differential.

The differential scheme creates a well-defined protection zone, encompassing everything between the two current transformers. Any fault existing in this protection zone is regarded as an internal fault, while any fault existing outside this protection zone is an external fault.

A differential scheme should therefore be able to respond to the smallest of internal faults, but restrain on the largest of external faults.

In practice, this is difficult to achieve – especially for very large through faults, due to the non-ideal nature of the current transformers used to measure the currents. The term used to specify the system’s ability to cope with these imperfections is called Through-fault Stability.

In modern IEDs (Intelligent Electronic Devices), the current in the current transformers do not directly control the operating coil which trips the circuit breakers, so the connectivity is not as it is shown in this example. In reality, the currents from the current transformers are simply input to the IED, where they are sampled and digitized.

The differential operation is then carried out by the IED’s software.

### Basic Transformer Differential Theory (VIDEO)

Reference // Substation Automation Principles by Michael J. Bergstrom

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### Edvard Csanyi

Electrical engineer, programmer and founder of EEP. Highly specialized for design of LV/MV switchgears and LV high power busbar trunking (<6300A) in power substations, commercial buildings and industry facilities. Professional in AutoCAD programming.

Apr 15, 2021

The fault that you give is outside the zone of differential relay!
in this case there will be no spill current hence no triping will occur.
tripping will only occur if the fault is inside the zone then there will be difference between two current!

2. Aung Kooo
Nov 28, 2020

33/0.4kV, 4000kVA. how to calculate knee point voltage and exciting current.

3. Electrical
Aug 22, 2018

Dear Sir,
We Have Transformer plus Cable differential protection achieved through 7SD610 Numerical Relay.
Recently We have observed that R phase outzone fault in other feeder cause activation of B phase differential protection without any fault. can u tell why?

4. Beryl
Feb 27, 2018

Very detailed but simple to understand piece.I am preparing to be tested for 33KV switching and the simple explanations in this article have made it very interesting for me to read

5. ULHAS VAJRE
Dec 11, 2016

Earlier I had asked few questions to Edward, but till date I didn’t get any reply from him. Is there any unwritten protocol that no replies shall be given, is that so??

6. Emmanuel
Dec 09, 2016

Could you, please, clarify how does thr alghorithim of the digital relay computes reading the fault?
With the static and electromechanic relays the basis was angle measurement. Static used the coincidence+ anti-coincidence principle of the formulae and integrated them so that by triggering the integrated value you would be able to tripp the switching device.
/as far as I know, digital devices use the DFT Discrete Fourier Transformation but I would be pleased if you could develop it so that it can be more ´´digestible´´.