## Why reactive power and PF correction?

Why reactive power and power factor correction are so important? Well, for experienced engineers, this is not the question but the fact. For young students who meet this matter and terms for the first time, it’s important to explain the matter very carefully, because much future knowledge will be built on its basis.

## Introduction to terms

In AC circuits, the current absorbed by a load can be represented by two components: active component I_{R} and reactive component I_{Q}.

**The active component I _{R}**, in phase with the supply voltage, is directly related to the output (and therefore to the part of electric energy converted into energy of different types: mechanical energy, light energy, thermal energy…);

**The reactive component I _{Q}**, in quadrature to the voltage, is used to generate the flow necessary for the conversion of powers through the electric or magnetic field and it is index of the transfer of energy between supply and load. Without this, there could be no net transfer of power, for example, thanks to the magnetic coupling in the core of a transformer or in the air gap of a motor.

In the most common case, in the presence of ohmic-inductive type loads, the total current I lags with respect to the active component I_{R}. Therefore, in an electrical installation, it is necessary to generate and transmit, in addition to the **active power P**, a certain **reactive power Q**, which is essential for the conversion of the electrical energy but is not available to the load because exchanged with the network.

The complex of the power generated and transmitted constitutes the **apparent power S**. Power factor cosϕ is defined as the ratio between the active component I_{R} and the total value of the current I; **Φ** is the phase angle between the voltage and the current.

**taking the necessary steps to increase the power factor in a defined section of the installation**by locally delivering the necessary reactive power so that the value of the current and consequently of the power flowing through the upstream network can be reduced, at the same required output power.

In this way, the lines, the generators and the transformers can be sized for a lower apparent power, as better explained in the following paragraphs.

- Reactive power and its effects
- The effects of low power factor
- Power Factor Correction
- Power Factor improvement at the load
- Capacitor Installations
- Energy Saving Costs using PFC

### 1. Reactive power and its effects

The necessary presence of reactive elements in AC circuits and the associated requirements of reactive power or VARs to service these elements cause significant problems in the operation of such AC supply systems.

The net reactive power requirements must be met by the source and this can have significant impact on the operation if some steps are not taken to alleviate the problem.

S = P + jQ =

**V × I***(where

**I***is the complex conjugate of I)

We define the** reactive power to be positive when it is absorbed** (as in a lagging power factor circuit).

a. Pure capacitance element – For a pure capacitance element, **P=0** and **I leads V by 90°** so that complex power is:

S = jQ = (V ∠0°) (I ∠90°)

S = V×I ∠−90°

**S = −jV×I**

Thus the capacitance element generates reactive power.

b. Inductive element – Similarly, for an inductive element, **P = 0** and **I lags V by 90°** so that:

S = jQ = (V ∠0°) (I ∠−90°)

S = V×I ∠+90°

**S = +jV×I**

Thus the inductance element absorbs reactive power. Most loads are net inductive and so they require reactive power to be supplied by the source. Similarly overhead lines are net absorbers of reactive power, but cables, with their high capacitance are net generators of reactive power and this has to be handled by the source.

The presence of reactive power in a load means that the power factor is reduced from unity and so it is best to operate at high power factor.

**it is to install additional inductance or capacitance**as required to alleviate the supply of the need to handle the reactive power. This is the general principle of power factor correction.

For a general (**lagging) power factor cosΦ** , the current lags the voltage by **Φ**, while for a leading power factor the current leads the voltage by **Φ**. The various phase relationships and the corresponding phasor diagrams are shown below.

##### Lagging circuit:

##### Leading circuit:

Note that (the convention says) reactive power is positive (absorbed) in lagging power factor circuits and is negative (generated) in leading power factor circuits.

Note also that:

**Total Current |I|** = √((I cosφ)^{2} + (I sinφ)^{2})

**Apparent power |S|** = √(P^{2} + Q^{2}) = √((VI cosφ)^{2} + (VI sinφ)^{2})

### 2. The effects of low power factor

There are two main problems associated with low power factor (or the presence of reactive power) in a load:

- Voltage drop
- Efficiency (and cost of energy supply)

#### 2.1 Voltage Drop

The reactive component of current, **I × sinφ** , causes unwanted voltage drop that affects the regulation at the load.

#### 2.2 Efficiency and cost

The reactive current (I sinφ ) also generates additional heat loss in the connecting lines and for this reason the supplier will impose limits on the load power factor by imposing an additional cost premium on low power factor loads.

**way of a charge on the peak kVA requirement of a load**so that reduction of the kVA by reduction of power factor is an economic proposition for the customer.

### 3. Power Factor Correction

The traditional means of correcting power factor for the typical lagging circuit is by installing capacitance to generate some of the reactive power required by the load so as to remove the necessity of the supply from providing it.

There are two configurations available for capacitance installation: **series and shunt connection**.

#### 3.1 Series Connection

In the diagram below, **V _{s}‘** is the source voltage without capacitance and

**V**is the source voltage with capacitance correction.

_{s}**The voltage regulation is:**

ΔV = |V_{S}| − |V_{R}|

Thus the added VAR generation is **Q _{C} = I^{2} X_{C}** and the resulting improvement (decrease) in the voltage regulation is:

**Q**

_{C}sinΦ / I volts**Series connection has some advantages and disadvantages:**

- The reduction in
**total I**is small so that the improvement in loss in the line is very small. - Series capacitance is very good for voltage regulation and for improving (smoothing) voltage fluctuations.
- The series capacitance helps to improve stability if the line reactance is high.
- Series connection is much less flexible than shunt connection in that the capacitance value is not easily able to be changed.

#### 3.2 Shunt Connection of Capacitance

**Note that:**

I’ = I_{R} + I_{C}

Q_{C} = V_{R} I_{C}

**Regulation in this case is:**

ΔV = I_{R}RcosΦ + I_{R}X_{L}sinΦ − I_{C}X_{L}

**And the voltage boost is:**

I_{C}X_{L} = Q_{C}X_{L} / V_{R}

**The advantages and disadvantages of shunt connection are:**

- Improves power factor and reduces line current significantly and thus reduces line losses significantly.
- Not as good as series connection for voltage smoothing.
- Has much greater flexibility of use than series as change of the value has no effect on load current.

In general, series connection is rarely used, except in some very high voltage long transmission lines where better voltage regulation is needed.

The use of shunt capacitors is almost universal for distribution systems and loads, where the flexibility of shunt connection allows automatic compensation using switched capacitor banks (static VAR compensators) that can adapt to changing load conditions.

##### Important Note:

In the above, the discussion has been for lagging power factor loads, the most common type. For leading power factor loads it is necessary to add in some means of absorbing reactive power such as series inductance.

**Alternatively, an option used on some transmission lines is the use of unloaded synchronous motors at the load end of the line:**

- When over-excited the synchronous motor will operate at leading power factor and generate VARs
- When under-excited the motor will operate at lagging power factor and absorb VARs.

### 4. Power Factor improvement at the load

The improvement of power factor at the consumers load will improve voltage regulation and the power transfer efficiency.

The basic aim is to increase **cosΦ (typically 0.55-0.8)** to some higher value** cosΦ’ (typically about 0.9-0.95)**.

This will reduce the current magnitude from **I** to **I’** and hence the line losses from **I ^{2}R** to

**I’**. Similarly, the reactive current component

^{2}R**I**will reduce to

_{Q}**I**, where:

_{Q}‘I_{C} = I_{Q} − I_{Q}‘

This can be achieved in either of two ways, depending on load requirements:

**At constant total real power (P):**This is done by reducing the total line current for the same total load P.**At constant total apparent power (S):**This is done by allowing the same total line current but increasing the total real power (P) at the load.

#### 4.1 Correction at constant real power

|S_{1}| = VI_{1}

|S_{2}| = VI_{2}

P = VI_{1} cosΦ_{1} = VI_{2} cosΦ_{2}

Q_{1} = VI_{1} sinΦ_{1}

Q_{2} = VI_{2} sinΦ_{2}

We need installed capacitance C to generate **reactive power of Q _{1} − Q_{2} VARs**. Thus we need:

ΔQ = Q_{1} − Q_{2} = P (tanΦ_{1} − tanΦ_{2})

**For shunt capacitance:**

ΔQ = I_{C}^{2}X_{C} = V_{C}^{2} / X_{C} = ωCV_{C}^{2}

**The reduction in line current is:**

I_{2} = I_{1} × cosΦ_{1} / cosΦ_{2}

**For example, for cosΦ _{1} = 0.65 and cosΦ_{1} = 0.90,**

I_{2} = 0.72 I_{1} **[a reduction of 28%]**

I_{2} = 0.52 I_{1}^{2} **[a reduction of 48%]**

#### 4.2 Correction at constant S

This method increases availability of real power for possible increase of load capacity for a fixed source current.

**Initially, at cosΦ _{1}, power P_{1} is available:**

P_{1} = S cosΦ_{1}

Q_{1} =S sinΦ_{1}

**After correction, at cosΦ _{2}, P_{2} is available:**

P_{2} = S cosΦ_{2}

Q_{2} = S sinΦ_{2}

To achieve this we require reactive power generation: **ΔQ = S(sinΦ _{1} − sinΦ_{2})**

**However the regulation is improved.**

### 5. Capacitor Installations

PFC installations (**Static VAR Compensators or SVCs**) are extensively used in transmission and distribution systems and in industry and commercial buildings where reactive power may be high. The capacitors are installed in banks made up in modular and separately switchable units which can range **from 7.5kVAR to 100kVAR or higher**.

Automatic power factor sensing is used and appropriate capacitance values are switched in and out as required, usually by thyristor switches.

**Synchronous motor compensation** is mostly used on transmission systems (when it is used).

### 6. Energy Saving Costs using PFC

Most items of large and extensive distributed equipment operate at relatively low power factors and thus benefit from power factor correction. To determine the benefit requires some study of the cost-benefit analysis of such capacitor installations.

Table 1 **– Typical power factors**

Source | Power factor |

Incandescent loads | 1.0 |

Heating loads | 0.95-1.0 |

Fluorescent lighting | 0.6 (about 0.95-0.97 when individually corrected) |

Large induction motors | 0.75-0.9 at full load |

Small induction motors | 0.6-0.85 at full load (fractional horsepower size) |

#### 6.1 Energy Metering and charging methods

Small consumers of electrical energy pay for their power by the individual kilowatthour (kWh) usage. There is no significant benefit from power factor improvement for small consumers.

For large users of energy, such as industry and commerce and similar establishments, the method of assessing charge may be one of a number of options. These are all based on a capacity charge basis where the peak demand is monitored and is used to assess the charge.

**They may be:**

- A daily capacity rate per kW peak ($/kW/day)
- A daily capacity rate per kVA peak ($/kVA/day)

**maximum half hourly kW or kVA power reading over the last 12 months**. Furthermore, the chargeable kW or kVA reading can only occur in peak times (2pm−8pm on working weekdays).

Note that whenever kVA or kVARs are used as the charge basis there is some potential for cost reduction by installing capacitors banks, or installations of VARs.

Typically, the cost of capacitors may be **about $20-$40 per kVAR**. This cost must be used with the amortized saving to determine the potential economic benefit. Normally a cost recovery time of a year or so would be aimed for. Any longer time would not be considered adequate benefit, although the added bonus of reduction of line losses should be included.

#### 6.2 Loss Reduction

The other savings benefit that comes with power factor correction occurs with the reduction of losses in the feeder connections. The per unit reduction in ohmic (I^{2}R ) loss due to reduction of line current is:

P U loss reduction = 1 − (PF_{old} / PF_{new})^{2}

Typically, line losses are about **3–7% of total load power usage**. Any reduction of the 3–7% will give substantial benefit if the load power consumption is high.

##### Example:

A **1000 kW load** is operated for **60 hours per week** from a 415V supply with** 7% loss** in the supply lines. The **load PF is 0.75** and the energy charge is **$0.10 per kWh**. What are the cost benefits of **increasing PF to 0.95**?

If the load power factor is increased to 0.95, the loss improvement is:

1 − (0.75 / 0.95)^{2} = 0.377 = 37.7%

Thus the new losses are 0.623 × 7% = **4.36 %**

Old kWh loss per week was: 0.07 × 1000 × 60 = **4200 kWh**

Energy cost was 4200 × $0.1 = **$420 per week**

New kWh loss per week: 0.0436 × 1000 × 60 = **2618 kWh**

Energy cost is now (2618) × $0.1 = **$261.8 per week**

Saving is 420 – 261.8 = $158.2 per week or $8,226 per annum. [$685.5 /month]

**For PF = 0.75**, S = 1333 kVA, Q = 882 kVAR

**For PF = 0.95**, S = 1053 kVA, Q = 329 kVAR

Thus, need

882 − 329 = 553 kVARof installed capacitance. If the cost of the capacitors is$20/kVAR, installation cost is$11,060. Time to achieve cost recovery is11,060 / 686 = 16.1 months.

#### 6.3 Inrush current

In addition to the harmonics problem, use of capacitor banks will also cause **transient HF inrush currents when they are energized**. These may cause some problems.

For a capacitor installation with reactance X_{C}, installed in shunt where there is inductive reactance X_{L} between the capacitor and the source, the inrush current is:

and frequency is:

Shunt capacitors are protected by fuses. Fuse links are usually sized at** 125% to 135% of the rated capacitor current**. This is to allow for overvoltage conditions, transient currents, harmonic. The rated current for a 3-phase capacitor bank is:

**Sources:**

*Reactive Power and Power Factor Correction Lecture**Power factor correction and harmonic filtering in electrical plants by ABB*

Am test engineer for Solar inverter and to test our inverter we use Inverter back to back,one inverter work as converter and other in Inverter mode,where the Losses supplied by a DC sources and both converter and Inverter are isolated with isolattion transformer

Recently test rig was upgraded with 7.5MVA Transformer, but transformer kept away from 100 meters away due to oil type transformer,this is connected with bus duct 7000A rated,now we measure lot of reactive component added due to the bus duct,Please give your thought to make it PF-1, is the only way to add capacitors in the network

Is it necessary to correct power factor in hydropower plant. If yes; on what condition and at what locations?

What device are you using, an induction generator? If so is it grid tied? IG’s produce power with a leading PF. This means the usual method of adding capacitance won’t work.

how to detect harmonics and whats the remedy to overcome it .I am going to install capacitor bank at stone crusher plant which has induction motors with dol and star Delta starter no vfds there .will it cause harmonics

capacitor banks are enough ??

Knowledge is power….

Very informative indeed. Thank you!

Very valuable information

In above calculation you are using the value of 0.623 and 0.436. I want know how they are getting and why. please inform me.

With regardas

Hanamantraya

Owesom

Valuable material.

nice article specially for the students.. but why i cant Save to PDF.. i am a premium member. thank you

Kind of confuse with meter billing methods as regards instrumentation and calibration if the energy meters mostly in kwh..

My question is how can a power factor correction be done on billings or meter readings in kwh…when no p.f or reactive componenet was not measured/bill…