Premium Membership ♕

Save 50% on all EEP Academy courses with Enterprise Membership Plan and study specialized LV/MV/HV technical articles & guides.

Home / Technical Articles / Specifying energy efficient motor, cabling and local power transformer

Why energy efficient? Let’s see.

Many energy saving actions can encourage specifiers and engineers to look closely at the savings which can be made by specifying an energy efficient version of a particular component.

Specifying energy efficient motor, cabling and local power transformer
Specifying energy efficient motor, cabling and local power transformer (photo credit:

This technical article presents the case for taking the important step and looking at the overall benefit of specifying energy efficient options throughout the system, looking at the motor and cabling together, and if appropriate, the local power transformer.

  1. The motor
  2. The cable
  3. The transformer

1. The Motor

As an example, consider a ventilation fan motor, working full time, at 100 metres from the distribution panel.

Rating kW% LoadOutput Power kWDuty hours/year 

Typical Motor parameters:

EfficiencyOutput PowerInput PowerAnnual ConsumptionCurrent per phase
Energy efficient906.5257.2563,5109.51

The input power is given by the following formula:

The input power formulae

At a unit cost of £0.0443 per unit, the annual saving is £97.02, while the incremental cost of the energy-efficient motor would be about £95.

Go back to energy efficient options ↑

The Cable

A conductor cross-section of 1.5 mm2 would be considered adequate – from a thermal rating point of view – to carry this current (< 10A). Such a cable would have a resistance of 25 milliohms per metre.

The power loss in the cable is:

pL = I2 × R

The reduction in power loss in the cable due to the use of an energy efficient motor is:

pD = (I12 – I22) × R
pD = (9.842 – 9.512) × 25 × 10-3 × 100
pD = 5.796 × 2.5 = 14.49 W

Energy saved per year = 127 kWh

But, if the cable size is chosen for energy efficiency, rather than the minimum safe size, much greater savings can be made!!

For a 1.5 mm2 cable supplying an energy efficient motor the power loss is:

= 9.512 × 25 × 10-3 x 100 = 226.1 W per phase, or 678.3 W total for all three phases.

Using, say, 10 mm2 cable would reduce the total loss to 103.1 W, giving an annual saving of

575.2 × 8,760 = 5,037 kWh

At a unit price of £0.0443 per unit, the annual saving would be £223.14. Since the cost of installation will not be significantly higher than for the smaller cable, the only additional cost is the purchase cost of the cable.

This table shows the power saving achieved so far:

For 6.525 kW output powerStandard motorEnergy efficient motor
1.5 mm2 cable [kW]10 mm2 cable [kW]
Input power8.1787.353
Overall efficiency [%]8089

The overall annual power saving is 7,227 kWh, or £320.16.

Go back to energy efficient options ↑

3. The Transformer

There are dozen of factors which should be considered when selecting local transformers (core losses, load losses, winding material, etc.). By careful selection of the motor and cabling we have already reduced the input power by 10%, and consequently the attributable transformer load loss by 21%.

Selecting a low loss transformer would reduce the loss further. Transformer load loss is proportional to the square of the load current, so the loss associated with an incremental load depends on the degree of loading.

Using the standard and low loss transformers from Table 1 and assuming that it is running at 80% load, the incremental loss associated with a 1 kW load for each transformer can be estimated at 24.4 W and 21.25 W respectively.

 Typical RES
(10% TDR)
Typical Industry userTypical RES
(5% TDR)
Loss capitalisation values per kilowatt£3,000/£625£3,988/£814£3,750/£780
Standard loss alternative
No-load loss 0.735 kW£2,205.00£2,931.18£2,756.25
Load loss 4.8 kW£3,000.00£3,907.20£3,744.00
Low loss alternative
No-load loss 0.38 kW£1,140.00£1,515.44£1,425.00
Load loss 4.08 kW£2,550.00£3,321.12£3,182.40
Amorphous steel alternative
No-load loss 0.145 kW£435.00£578.26£543.75
Load loss 4.77 kW£2,981.25£3,882.78£3,720.60

TDR – Test discount rate
REC – Regional Electricity Companies

For the incremental load of the motor, the additional losses are 195.2 W for the standard and 170 W for the low loss transformer, so that the low loss transformer saves a further 221 kWh per annum. The additional cost of selecting a low loss transformer is equivalent to £5.37 per kW of rating (based on a 315 kW unit), so that attributable to the motor load (remembering that the overall loading is 80%) is £53.60.

Input power [kW]
For 6.525 kW output powerStandard motor
1.5 mm2 cable standard transformer (kW)
Energy efficient motor
10 mm2 cable low loss transformer (kW)
Input power to motor7.5007.250
Input power to cable8.1787.353
– plus incremental transformer loss8.3737.523
Annual consumption73,347 kWh65,901 kWh

The overall saving is 7,446 kWh per year, equivalent to £329.85 per year (at £0.0443 per unit).

The payback period will be different for each element. In this example it is less than 1 year for the motor, and about 7 years for the transformer – a short time compared to the life expectancy of a transformer.

It must be remembered that the selection of more efficient downstream components, including cabling, reduces losses in other components upstream.

Go back to energy efficient options ↑

Reference // Electrical Energy Efficiency by Copper Development Association

Premium Membership

Get access to premium HV/MV/LV technical articles, electrical engineering guides, research studies and much more! It helps you to shape up your technical skills in your everyday life as an electrical engineer.
More Information

Edvard Csanyi

Electrical engineer, programmer and founder of EEP. Highly specialized for design of LV/MV switchgears and LV high power busbar trunking (<6300A) in power substations, commercial buildings and industry facilities. Professional in AutoCAD programming.


  1. Asamoah Boateng Victor
    Sep 19, 2020

    Hello EEP personnel’s, am very happy I have you as my electrical engineering followers, I will be glad to be part of this platform and get a lot of electrical articles. Thank you

    Jan 10, 2017

    Its nothing about specification parameters of the equipment. Its general theory and calculations with low loss and related results. If possible please try to provide some information if standard and energy efficient equipment are manufactured by the manufacturer or if there is any standard code (national or international) providing difference for them.

Leave a Reply to Asamoah Boateng Victor

Tell us what you're thinking. We care about your opinion! Please keep in mind that comments are moderated and rel="nofollow" is in use. So, please do not use a spammy keyword or a domain as your name, or it will be deleted. Let's have a professional and meaningful conversation instead. Thanks for dropping by!

  +  seventy one  =  seventy nine

Learn How to Design Power Systems

Learn to design LV/MV/HV power systems through professional video courses. Lifetime access. Enjoy learning!

Subscribe to Weekly Newsletter

Subscribe to our Weekly Digest newsletter and receive free updates on new technical articles, video courses and guides (PDF).
EEP Academy Courses - A hand crafted cutting-edge electrical engineering knowledge