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How Power Factor Corection Works

As with any equipment, an electrical system handles its job to some degree of efficiency ranging from poor to excellent. The measure of electrical…

Understanding Power Factor

As with any equipment, an electrical system handles its job to some degree of efficiency ranging from poor to excellent. The measure of electrical efficiency is known as Power Factor.

The motors and other inductive equipment in a plant require two kinds of electric power. One type is working power, measured by the kilowatt (kW). This is what actually powers the equipment and performs useful work. Secondly, inductive equipment needs magnetizing power to produce the flux necessary for the operation of inductive devices. The unit of measurement of magnetizing or reactive power is the kilovar (kVAR). The working power (kW) and reactive power (kVAR) together make up apparent power which is measured in kilovoltamperes (kVA).

Most AC power systems require both kW (kilowatts) and kVAR (kilovars). Capacitors installed near the loads in a plant are the most economical and efficient way of supplying these kilovars. Low voltage capacitors are traditionally a high reliability maintenance-free device.

On the spot delivery of magnetizing current provided by capacitors means that kilovars do not have to be sent all the way from the utility generator to you. This relieves both you and your utility of the cost of carrying this extra kilovar load. The utility charges you for this reactive power in the form of a direct, or indirect power factor penalty charge.

In addition, you’ll gain system capacity, improve voltage and reduce your power losses.

Title:How Power Factor Corection Works
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Hower Power Factor Works

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Page edited by E.C. (Google).

7 Comments


  1. Emin M
    Feb 20, 2017

    The download link does not work. The file needs to be reuploaded or link needs to be updated


  2. Josè Severino Queiroz
    Feb 02, 2017

    Excuse me ! Is there any diference between the theorical calculation and mesured result? About power factor and reactive energie?


  3. Thiagarajan
    Sep 26, 2016

    sir, i have a doubt,is anycalculated time to reach the desired power factor for example a load of 630 kw and capacitor bank is 575 kvar present p.f is 0.13 required p.f is 0.98 at what time the p.f will reach.
    regards,
    thiagarajan


  4. waleed
    Apr 16, 2015

    So Sorry I forgot to thank you for the interesting information


  5. waleed
    Apr 16, 2015

    I think you can provide us with new books of electronics and electricity


  6. Raffy F. Yanuario
    Oct 11, 2014

    very good info…


  7. MODUGULA
    Mar 06, 2013

    it’s fantastic

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